
MATH QUESTION OF THE DAY 


Peter got 30% of the maximum marks in an examination and failed by 10 marks. However, Paul who took the same examination got 40% of the total marks and got 15 marks more than the passing marks. What was the passing marks in the examination?
A. 35 B. 250 C. 75 D. 85 E. 90






Student: 2/23/2010 11:50:47 AM 

Answer is A  250. 





Student: 2/23/2010 11:51:01 AM 

Sorry it was B250. 





Student: 2/24/2010 1:40:15 AM 

ans B.250






Student: 2/24/2010 4:42:13 AM 

B 





Student: 6/7/2010 7:59:34 PM 

don't understand... 





Student: 6/13/2010 5:16:58 AM 

250 is the full marks answer is D 





Student: 9/24/2010 3:45:40 PM 

let total marks be X student 1 3x/10+10 =x student 2 4x/1015=x equating the two, x =250
thanks 





Student: 11/18/2010 8:30:51 AM 

what's the hell the correct answer by admin is? don't they no, simple rule of mathmatics? 





Student: 4/24/2011 8:18:51 PM 

Answer is D.
Let x be the total marks and p be the passing marks. Peter > 30/100*x + 10 = p Paul > 40/100*x  15 = p Solving this x = 250 and p = 85
 Dimple 





Student: 5/23/2011 12:44:22 AM 

This is very simple to set up:
"Peter got 30% of the maximum marks in an examination and failed by 10 marks."
This means his score of 30% of the maximum score = passing score  10 marks
Let x be the maximum score (mark) and p be a passing score. For Peter then,
.3*x = p  10
Following the same process, we can find for Paul,
.4*x = p+15
Our two equations then are:
.3*x = p10 (Eq 1) .4*x = p+15 (Eq 2)
The question only wants to know what the passing score is, so forget about x and just find p. The easiest way to do this is to divide Eq 1 by Eq 2:
.3/.4 = (p10)/(p+15) > 3/4 = (p10)/(p+15) > (3/4)(p+15) = p10 > 3(p+15) = 4p  40 > 3p + 45 = 4p  40 > p = 85 





Student: 5/23/2011 12:44:26 AM 

This is very simple to set up:
"Peter got 30% of the maximum marks in an examination and failed by 10 marks."
This means his score of 30% of the maximum score = passing score  10 marks
Let x be the maximum score (mark) and p be a passing score. For Peter then,
.3*x = p  10
Following the same process, we can find for Paul,
.4*x = p+15
Our two equations then are:
.3*x = p10 (Eq 1) .4*x = p+15 (Eq 2)
The question only wants to know what the passing score is, so forget about x and just find p. The easiest way to do this is to divide Eq 1 by Eq 2:
.3/.4 = (p10)/(p+15) > 3/4 = (p10)/(p+15) > (3/4)(p+15) = p10 > 3(p+15) = 4p  40 > 3p + 45 = 4p  40 > p = 85 





Student: 7/9/2011 8:38:02 AM 

the question says, paul got 40% of the total marks (and not the max marks) so how do you arrive at the second equation as 0.4x=p+15??? 










Answer 




