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 Peter got 30% of the maximum marks in an examination and failed by 10 marks. However, Paul who took the same examination got 40% of the total marks and got 15 marks more than the passing marks. What was the passing marks in the examination? A. 35B. 250C. 75D. 85E. 90
Student: 2/23/2010 11:50:47 AM Answer is A - 250.
Student: 2/23/2010 11:51:01 AM Sorry it was B-250.
Student: 2/24/2010 1:40:15 AM ans- B.250
Student: 2/24/2010 4:42:13 AM B
Student: 6/7/2010 7:59:34 PM don't understand...
Student: 6/13/2010 5:16:58 AM 250 is the full marks answer is D
Student: 9/24/2010 3:45:40 PM let total marks be Xstudent 1 3x/10+10 =xstudent 2 4x/10-15=xequating the two, x =250thanks
Student: 11/18/2010 8:30:51 AM what's the hell the correct answer by admin is? don't they no, simple rule of mathmatics?
Student: 4/24/2011 8:18:51 PM Answer is D.Let x be the total marks and p be the passing marks.Peter --> 30/100*x + 10 = pPaul --> 40/100*x - 15 = pSolving this x = 250and p = 85-- Dimple
Student: 5/23/2011 12:44:22 AM This is very simple to set up:"Peter got 30% of the maximum marks in an examination and failed by 10 marks."This means his score of 30% of the maximum score = passing score - 10 marksLet x be the maximum score (mark) and p be a passing score. For Peter then,.3*x = p - 10Following the same process, we can find for Paul,.4*x = p+15Our two equations then are:.3*x = p-10 (Eq 1).4*x = p+15 (Eq 2)The question only wants to know what the passing score is, so forget about x and just find p. The easiest way to do this is to divide Eq 1 by Eq 2:.3/.4 = (p-10)/(p+15)-> 3/4 = (p-10)/(p+15)-> (3/4)(p+15) = p-10-> 3(p+15) = 4p - 40-> 3p + 45 = 4p - 40--> p = 85
Student: 5/23/2011 12:44:26 AM This is very simple to set up:"Peter got 30% of the maximum marks in an examination and failed by 10 marks."This means his score of 30% of the maximum score = passing score - 10 marksLet x be the maximum score (mark) and p be a passing score. For Peter then,.3*x = p - 10Following the same process, we can find for Paul,.4*x = p+15Our two equations then are:.3*x = p-10 (Eq 1).4*x = p+15 (Eq 2)The question only wants to know what the passing score is, so forget about x and just find p. The easiest way to do this is to divide Eq 1 by Eq 2:.3/.4 = (p-10)/(p+15)-> 3/4 = (p-10)/(p+15)-> (3/4)(p+15) = p-10-> 3(p+15) = 4p - 40-> 3p + 45 = 4p - 40--> p = 85
Student: 7/9/2011 8:38:02 AM the question says, paul got 40% of the total marks (and not the max marks) so how do you arrive at the second equation as 0.4x=p+15??? Answer Copyright © 2009 GMAT Score. All Rights reserved.