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MATH QUESTION OF THE DAY 


If the diagonal and the area of a rectangle are 25 in and 168 in^{2}, what is the length of the rectangle?
A. 17 B. 31 C. 12 D. 24 E. 30






Student: 2/22/2010 4:19:30 PM 

explain it plzz 





Student: 3/16/2010 5:13:12 PM 

Using the rule a2+b2=c2, we know that the value of a and b each squared has to eaual to 25^2 which equals 625. Since 25 is the diagonal, we also know that to be the longest side so that means that the other two sides have to be 24 & 7 since 24^2=576 and 7^2=49. 49+576=625 





Student: 4/24/2011 9:35:36 PM 

Let l and b be the length and breadth of rectangle resp.
l^2 + b^2 = 25^2 = 625 and lb = 168 consider the factors of 168 = 2 * 2 * 2 * 3 * 7 One can actually solve the equation but to save the time you might want to just make a trial method. So look at the options and see what specifies both the conditions. we can have l = 24 and b = 7 that specifies both the conditions. 










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