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MATH QUESTION OF THE DAY

 The circumference of the front wheel of a cart is 30 ft long and that of the back wheel is 36 ft long. What is the distance traveled by the cart, when the front wheel has done five more revolutions than the rear wheel? A. 20 ftB. 25 ftC. 750 ftD. 900 ftE. 1000 ft
Student: 2/21/2010 11:53:41 AM
 Very good website
Student: 2/21/2010 3:39:25 PM
 itz D
Student: 2/22/2010 2:19:56 AM
 D
Student: 2/22/2010 4:18:07 PM
 need explanation ?
Student: 2/22/2010 9:40:46 PM
 CAN ANY ONE PLZ SOLVE IT I DONT GET IT PLZ
Student: 2/24/2010 9:06:37 AM
 front wheel has taken 5 extra rounds and 5 rounds = 150ft ( 30*5) the back wheel covers 6ft more in one rounds compared to front wheel so to cover 150 ft more it has to take 25 rounds. Therefore , we conclude that the back wheel has taken 25 rounds and front wheel has taken 30 rounds,(since they wheel travel equal distance) So the distance covered is 30*30=36*25=900ft
Student: 4/24/2011 9:28:14 PM
 The circumference of the front wheel of a cart is 30 ft long and that of the back wheel is 36 ft long. What is the distance traveled by the cart, when the front wheel has done five more revolutions than the rear wheel? 5 revolutions means 30*5 = 150 ft traveled.Distance traveled by the front wheel = 30*x + 150Distance traveled by the rear wheel = 36 * xDistances are equal so --> 30 * x + 150 = 36 * xsolving x = 25 ft.Distance traveled by the cart 30 * 25 + 150 OR36 * 25gives distance = 900 ft.